User-defined functions

A function may be defined using syntax such as the following:

Example 12-1. Pseudo code to demonstrate function uses <?php function foo($arg_1, $arg_2, /* ..., */ $arg_n) {    echo "Example function.\n";    return $retval; } ?>

Any valid PHP code may appear inside a function, even other functions and class definitions.

In PHP 3, functions must be defined before they are referenced. No such requirement exists in PHP 4. Except when a function is conditionally defined such as shown in the two examples below.

When a function is defined in a conditional manner such as the two examples shown. Its definition must be processed prior to being called.

Example 12-2. Conditional functions <?php $makefoo = true; /* We can't call foo() from here    since it doesn't exist yet,    but we can call bar() */ bar(); if ($makefoo) {   function foo()   {    echo "I don't exist until program execution reaches me.\n";   } } /* Now we can safely call foo()    since $makefoo evaluated to true */ if ($makefoo) foo(); function bar() {   echo "I exist immediately upon program start.\n"; } ?>

Example 12-3. Functions within functions <?php function foo() {   function bar()   {    echo "I don't exist until foo() is called.\n";   } } /* We can't call bar() yet    since it doesn't exist. */ foo(); /* Now we can call bar(),    foo()'s processesing has    made it accessible. */ bar(); ?>

PHP does not support function overloading, nor is it possible to undefine or redefine previously-declared functions.

PHP 3 does not support variable numbers of arguments to functions, although default arguments are supported (see Default argument values for more information). PHP 4 supports both: see Variable-length argument lists and the function references for func_num_args(), func_get_arg(), and func_get_args() for more information.